Hi,
I am using lsode to solve a simple ODE on Octave
2.1.72.The ode is:
Solve: y''(t) + y(t) =0
such that:
y(0)=3 & y(pi/2)=3
My code for this is:
-------- file f.m ---------
function xdot = f (x, t)
xdot = zeros (2,1);
xdot(1) = x(2);
xdot(2) = -x(1);
endfunction
---- end of f.m -----
-------- file ode.m ---------
l = linspace (0, pi/2, 20);
y_min=[3;3];
psi = lsode( "f", y_min, l );
plot(l,psi(:,1));
---- end of ode.m -----
I am getting correct answer with this. But lsode requires y_min which is actually the value of x(1) and x(2) at t=0. I have the value of x(1) at t=0 and t=pi/2.(I got the value of x(2) at t=0 by solving this on Matlab and then solved this by adding y_min=[3;3]; here). How can I use the given boundary conditions so that I don't need the values of x(2) to solve the problem.
Thank you
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