> x=1:80
>
> I want to sum up first 8 elements of x, then again next 8 elements of x,
> then again another 8 elements..... So, my new vector should look like:
>
> c(36,100,164,228,292,356,420,484,548,612)
>
> I used:
>
> aggregate(x,list(rep(1:10,each=8)),sum)[-1]
>
> or
>
> rowsum(x,group=rep(1:10,each=8))
>
> But without grouping, can I achieve the required? Any other ways of
> doing this?
This works:
colSums(matrix(x, nrow=8))
I'm not sure if you benefit over using the methods you described though.
Regards,
Richie.
Mathematical Sciences Unit
HSL
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Regards,
Richie.
Mathematical Sciences Unit
HSL
