Edsko de Vries wrote:
> sum :: Tree -> Int
> sum t = sum' [t] 0
> where
> sum' [] acc = acc
> sum' (Leaf i : ts) acc = sum' ts $! (i + acc)
> sum' (Node l r : ts) acc = sum' (l : r : ts) acc
Because of $!, you should compare the Leaf case to foldl', not foldl.
The Node case can be said to mimic a stack using heap resource.
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