Hello Luca.
Dr. Ottorino-Luca Pantani wrote:
...
c(1803.02, 193.51, 3.47)
Each solution is to be taken with 3 different pipettes (5000, 250 and 10
µL Volume max) and each of those delivers volumes in steps of 50 µL, 5
µL or 1µL, respectively
Since the above values would eventually become
c(1800, 195, 3)
...
You find a complete solution at
http://albertosantini.blogspot.com/2008/05/mround.htmlIt checks the sign of the number and the multiple and it hacks the issue of rounding off a 5 respect IEC 60559 standard.
The test cases are:
mround(10, 3) # 9
mround(-10, -3) # -9
mround(1.3, 0.2) # 1.4
mround(5, -2) # error
mround(1.7, 0.2) # 1.8
mround(321.123, 0.12) # 321.12
mround(1803.02, 50) # 1800
mround(193.51, 5) # 195
mround(3.47, 1) # 3
Regards,
Alberto