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Format integer
by Anh Tran
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Hi,
What's one way to convert an integer to a string with preceding 0's? such that '13' becomes '00000000013' to be put into a string I've tried formatC, but they removes all the zeros and replace it with blanks Thanks -- Regards, Anh Tran [[alternative HTML version deleted]] ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Tony Plate
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Try something like one of these (as documented in ?formatC)
> formatC(13, flag="0", width=10) [1] "0000000013" > sprintf("%010g", 13) [1] "0000000013" > Anh Tran wrote: > Hi, > What's one way to convert an integer to a string with preceding 0's? > such that > '13' becomes '00000000013' > to be put into a string > > I've tried formatC, but they removes all the zeros and replace it with > blanks > > Thanks > ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Uwe Ligges
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Anh Tran wrote: > Hi, > What's one way to convert an integer to a string with preceding 0's? > such that > '13' becomes '00000000013' > to be put into a string > > I've tried formatC, but they removes all the zeros and replace it with > blanks Not so for me: formatC(13, digits=10, flag="0") Uwe LIgges > > Thanks > ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Anh Tran
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Thanks. formatC(flag) works.
But it's awefully slow. I try to do that for 65000 numbers (generating ID for each item) and it seems like forever. Is there any faster way? Thank all. Anh Tran On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges < ligges@...> wrote: > > > Anh Tran wrote: > > > Hi, > > What's one way to convert an integer to a string with preceding 0's? > > such that > > '13' becomes '00000000013' > > to be put into a string > > > > I've tried formatC, but they removes all the zeros and replace it with > > blanks > > > > Not so for me: > > formatC(13, digits=10, flag="0") > > Uwe LIgges > > > > > Thanks > > > > -- Regards, Anh Tran [[alternative HTML version deleted]] ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Charilaos Skiadas-3
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On May 12, 2008, at 5:22 PM, Anh Tran wrote:
> Hi, > What's one way to convert an integer to a string with preceding 0's? > such that > '13' becomes '00000000013' > to be put into a string > > I've tried formatC, but they removes all the zeros and replace it with > blanks formatC(13, width=10, format="d", flag="0") > Thanks > > -- > Regards, > Anh Tran Haris Skiadas Department of Mathematics and Computer Science Hanover College ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Uwe Ligges-3
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Anh Tran wrote: > Thanks. formatC(flag) works. > > But it's awefully slow. I try to do that for 65000 numbers (generating ID > for each item) and it seems like forever. On my not that recent laptop: > system.time(formatC(1:65000, width=10, flag="0")) user system elapsed 1.92 0.00 1.94 I think 2 seconds is less than "forever". Uwe Ligges > Is there any faster way? > > Thank all. > > Anh Tran > > On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges < > ligges@...> wrote: > >> >> Anh Tran wrote: >> >>> Hi, >>> What's one way to convert an integer to a string with preceding 0's? >>> such that >>> '13' becomes '00000000013' >>> to be put into a string >>> >>> I've tried formatC, but they removes all the zeros and replace it with >>> blanks >>> >> Not so for me: >> >> formatC(13, digits=10, flag="0") >> >> Uwe LIgges >> >> >> >>> Thanks >>> >>> > > ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Anh Tran
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Yea, thanks all. I checked back and I got a few things mistyped.
The array is 650,000 and it took 25 seconds :p. It's acceptable. Just that I had too many variable at the time I ran it. Also, seems like sprintf is a little faster. Thanks all. Anh Tran On Mon, May 12, 2008 at 2:55 PM, Uwe Ligges <ligges@...> wrote: > > > Anh Tran wrote: > > > Thanks. formatC(flag) works. > > > > But it's awefully slow. I try to do that for 65000 numbers (generating > > ID > > for each item) and it seems like forever. > > > > On my not that recent laptop: > > > system.time(formatC(1:65000, width=10, flag="0")) > user system elapsed > 1.92 0.00 1.94 > > > I think 2 seconds is less than "forever". > > Uwe Ligges > > > > > > > Is there any faster way? > > > > Thank all. > > > > Anh Tran > > > > On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges < > > ligges@...> wrote: > > > > > > > Anh Tran wrote: > > > > > > Hi, > > > > What's one way to convert an integer to a string with preceding 0's? > > > > such that > > > > '13' becomes '00000000013' > > > > to be put into a string > > > > > > > > I've tried formatC, but they removes all the zeros and replace it > > > > with > > > > blanks > > > > > > > > Not so for me: > > > > > > formatC(13, digits=10, flag="0") > > > > > > Uwe LIgges > > > > > > > > > > > > Thanks > > > > > > > > > > > > > > > > -- Regards, Anh Tran [[alternative HTML version deleted]] ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Phil Spector
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I guess "little" means different things to different people:
> x = sample(1:100,650000,replace=TRUE) > system.time(a<-formatC(x,digits=10,flag='0')) user system elapsed 32.854 0.444 34.813 > system.time(b<-sprintf("%011d",x)) user system elapsed 0.352 0.012 0.363 If you look at the definitions of the functions, you'll see that formatC is written in R, and sprintf uses a single call to an .Internal function. I - Phil Spector Statistical Computing Facility Department of Statistics UC Berkeley spector@... On Mon, 12 May 2008, Anh Tran wrote: > Yea, thanks all. I checked back and I got a few things mistyped. > The array is 650,000 and it took 25 seconds :p. It's acceptable. Just that I > had too many variable at the time I ran it. > > Also, seems like sprintf is a little faster. > > Thanks all. > > Anh Tran > > > On Mon, May 12, 2008 at 2:55 PM, Uwe Ligges <ligges@...> > wrote: > >> >> >> Anh Tran wrote: >> >>> Thanks. formatC(flag) works. >>> >>> But it's awefully slow. I try to do that for 65000 numbers (generating >>> ID >>> for each item) and it seems like forever. >>> >> >> On my not that recent laptop: >> >>> system.time(formatC(1:65000, width=10, flag="0")) >> user system elapsed >> 1.92 0.00 1.94 >> >> >> I think 2 seconds is less than "forever". >> >> Uwe Ligges >> >> >> >> >> >> >> Is there any faster way? >>> >>> Thank all. >>> >>> Anh Tran >>> >>> On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges < >>> ligges@...> wrote: >>> >>> >>>> Anh Tran wrote: >>>> >>>> Hi, >>>>> What's one way to convert an integer to a string with preceding 0's? >>>>> such that >>>>> '13' becomes '00000000013' >>>>> to be put into a string >>>>> >>>>> I've tried formatC, but they removes all the zeros and replace it >>>>> with >>>>> blanks >>>>> >>>>> Not so for me: >>>> >>>> formatC(13, digits=10, flag="0") >>>> >>>> Uwe LIgges >>>> >>>> >>>> >>>> Thanks >>>>> >>>>> >>>>> >>> >>> > > > -- > Regards, > Anh Tran > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@... mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Prof Brian Ripley
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This is one of those problems where the fine details matter.
1) The version of R. I optimized sprintf() for long inputs and a single format in R 2.7.0 -- the differences are mainly for multiple inputs and where coercion is needed. See also below. 2) The system. My home system with an Intel Core 2 Duo is usually about the same speed as my office desktop with dual Opterons. But not here: Home: > system.time(a<-formatC(x,digits=10,flag='0')) user system elapsed 9.705 0.088 9.810 > system.time(b<-sprintf("%011d",x)) user system elapsed 0.283 0.000 0.283 Office: > system.time(a<-formatC(x,digits=10,flag='0')) user system elapsed 15.851 0.125 16.007 > system.time(b<-sprintf("%011d",x)) user system elapsed 0.816 0.001 0.818 and my Windows laptop is similar to the second here. So a speed-up of 95x seems atypical. On Mon, 12 May 2008, Phil Spector wrote: > I guess "little" means different things to different people: > >> x = sample(1:100,650000,replace=TRUE) >> system.time(a<-formatC(x,digits=10,flag='0')) > user system elapsed > 32.854 0.444 34.813 >> system.time(b<-sprintf("%011d",x)) > user system elapsed > 0.352 0.012 0.363 > > If you look at the definitions of the functions, you'll see > that formatC is written in R, and sprintf uses a single call > to an .Internal function. I Not really: the meat of formatC() is a .C call. In this case it is calling format.default(), also a .Internal. But profiling shows that most of the time here is spent in paste(), another function which was optimized in 2.7.0. (I see 2.7.0 as 1.7x faster than 2.6.2 on formatC here.) But although sprintf is more flexible, on most problems it will be substantially faster. > - Phil Spector > Statistical Computing Facility > Department of Statistics > UC Berkeley > spector@... > > > > On Mon, 12 May 2008, Anh Tran wrote: > >> Yea, thanks all. I checked back and I got a few things mistyped. >> The array is 650,000 and it took 25 seconds :p. It's acceptable. Just that >> I >> had too many variable at the time I ran it. >> >> Also, seems like sprintf is a little faster. >> >> Thanks all. >> >> Anh Tran >> >> >> On Mon, May 12, 2008 at 2:55 PM, Uwe Ligges >> <ligges@...> >> wrote: >> >>> >>> >>> Anh Tran wrote: >>> >>>> Thanks. formatC(flag) works. >>>> >>>> But it's awefully slow. I try to do that for 65000 numbers (generating >>>> ID >>>> for each item) and it seems like forever. >>>> >>> >>> On my not that recent laptop: >>> >>>> system.time(formatC(1:65000, width=10, flag="0")) >>> user system elapsed >>> 1.92 0.00 1.94 >>> >>> >>> I think 2 seconds is less than "forever". >>> >>> Uwe Ligges >>> >>> >>> >>> >>> >>> >>> Is there any faster way? >>>> >>>> Thank all. >>>> >>>> Anh Tran >>>> >>>> On Mon, May 12, 2008 at 2:36 PM, Uwe Ligges < >>>> ligges@...> wrote: >>>> >>>> >>>>> Anh Tran wrote: >>>>> >>>>> Hi, >>>>>> What's one way to convert an integer to a string with preceding 0's? >>>>>> such that >>>>>> '13' becomes '00000000013' >>>>>> to be put into a string >>>>>> >>>>>> I've tried formatC, but they removes all the zeros and replace it >>>>>> with >>>>>> blanks >>>>>> >>>>>> Not so for me: >>>>> >>>>> formatC(13, digits=10, flag="0") >>>>> >>>>> Uwe LIgges >>>>> >>>>> >>>>> >>>>> Thanks >>>>>> >>>>>> >>>>>> >>>> >>>> >> >> >> -- >> Regards, >> Anh Tran >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@... mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > ______________________________________________ > R-help@... mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Brian D. Ripley, ripley@... Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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Re: Format integer
by Esmail Bonakdarian-4
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Anh Tran wrote:
> Hi, > What's one way to convert an integer to a string with preceding 0's? > such that > '13' becomes '00000000013' > to be put into a string > > I've tried formatC, but they removes all the zeros and replace it with > blanks Hi, try sprintf: >i=13 > cat(sprintf("%05d\n", i)) 00013 > HTH, Esmail ______________________________________________ R-help@... mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. |
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